z^2-(2+5i)-3+5i=0

Solution for z^2-(2+5i)-3+5i=0 equation:

Simplifying
z2 + -1(2 + 5i) + -3 + 5i = 0
z2 + (2 * -1 + 5i * -1) + -3 + 5i = 0
z2 + (-2 + -5i) + -3 + 5i = 0

Reorder the terms:
-2 + -3 + -5i + 5i + z2 = 0

Combine like terms: -2 + -3 = -5
-5 + -5i + 5i + z2 = 0

Combine like terms: -5i + 5i = 0
-5 + 0 + z2 = 0
-5 + z2 = 0

Solving
-5 + z2 = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + z2 = 0 + 5

Combine like terms: -5 + 5 = 0
0 + z2 = 0 + 5
z2 = 0 + 5

Combine like terms: 0 + 5 = 5
z2 = 5

Simplifying
z2 = 5

Take the square root of each side:
z = {-2.236067978, 2.236067978}